Maths Olympiad Prep

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Geometry Difficulty 4.8 AIME Find the answer

Let ABCDA B C D be a unit square. A circle with radius 3249\frac{32}{49} passes through point DD and is tangent to side ABA B at point EE. Then DE=mnD E=\frac{m}{n}, where m,nm, n are positive integers and gcd(m,n)=1\operatorname{gcd}(m, n)=1. Find 100m+n100 m+n.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Let OO be the center of the circle and let FF be the intersection of lines OEO E and CDC D. Also let r=32/49r=32 / 49 and x=DFx=D F. Then we know x2+(1r)2=DF2+OF2=DO2=r2x^{2}+(1-r)^{2}=D F^{2}+O F^{2}=D O^{2}=r^{2} which implies that x2+12r=0x^{2}+1-2 r=0, or 1+x2=2r1+x^{2}=2 r. Now, DE=DF2+EF2=1+x2=2r=64/49=8/7D E=\sqrt{D F^{2}+E F^{2}}=\sqrt{1+x^{2}}=\sqrt{2 r}=\sqrt{64 / 49}=8 / 7

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