In quadrilateral ABCDABCDABCD, ∠ABC=∠ADC=90∘\angle ABC = \angle ADC = 90^{\circ}∠ABC=∠ADC=90∘, AD=DCAD = DCAD=DC and AB+BC=20AB + BC = 20AB+BC=20 cm. What is the area in cm2^22 of quadrilateral ABCDABCDABCD?