Maths Olympiad Prep

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Algebra Difficulty 2.0 Junior Prove it United Kingdom

The real numbers xx, yy and zz are a solution (x,y,z)(x, y, z) of the equation (x2−9)2+(y2−4)2+(z2−1)2=0(x^2 - 9)^2 + (y^2 - 4)^2 + (z^2 - 1)^2 = 0. How many different possible values are there for x+y+zx + y + z?

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