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Problem 178

Number theory Difficulty 1.2 Multiple choice CEMC Gauss (Grade 8) · Canada · 2019

How many positive integers less than 100 are divisible by both 3 and 7?

Pick one

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Official solution

When −37-37 and 11 are added, the result is −37+11=−26-37+11=-26. The correct answer is (A).

Alternately, the result can be found by subtracting, −26−11=−37-26-11=-37.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.