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Problem 333

Algebra Difficulty 2.3 Multiple choice CEMC Fermat · Canada · 2022

If 10x+y=7510x + y = 75 and 10y+x=5710y + x = 57 for some positive integers
xx and yy, the value of x+yx + y is

Pick one

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Official solution

Since 10x+y=7510x + y = 75 and 10y+x=5710y + x = 57, then (10x+y)+(10y+x)=75+57(10x + y) + (10y + x) = 75 + 57 and so
11x+11y=13211x + 11y = 132 Dividing by 11, we
get x+y=12x + y = 12.

(We could have noticed initially that (x,y)=(7,5)(x,y)=(7,5) is a pair that satisfies the
two equations, thence concluding that x+y=12x+y=12.)

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.