The list is an example of an increasing list of five positive integers in which the first and second integers add to the third, the second and third add to the fourth, and the third and fourth add to the fifth. How many such lists of five positive integers have 124 as the fifth integer?
Problem 932
Pick one
Official solution
If the first positive integer in the list is and the second is , then the third integer is , the fourth is or , and the fifth is or .
Thus, we are asked to find the number of pairs of positive integers and , where is less than (since the list is increasing), and for which .
What is the largest possible value for ?
If , then which is too large since . (Note that a larger value of makes even larger.)
If , then .
However in this case, we get that , which is not possible since is a positive integer.
If , then and so or .
Thus, the largest possible value for is 40.
What is the smallest value for ?
If , then and so or .
If , then .
However in this case, we get that , which is not possible since is a positive integer.
If , then and so or .
However, if the first integer in the list is 26, then the second integer can not equal 24 since the list is increasing.
Smaller values of will give larger values of , and so the smallest possible value of is 26.
From the values of attempted thus far, we notice that when is an odd integer, is also odd (since the product of two odd integers is odd), and is odd (since the difference between an even integer and an odd integer is odd).
So when is odd, is odd, and so is odd (since ).
However, is even for every choice of the integer and so cannot be odd.
Conversely, when is even, is even (as required), and so all even integer values of from 26 to 40 inclusive will satisfy the requirements.
These values of are , and so there are 8 such lists of five integers that have 124 as the fifth integer.
Here are the 8 lists: ; ; ; ; ; ; ; .