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Problem 425

Number theory Difficulty 2.7 Multiple choice CEMC Gauss (Grade 7) · Canada · 2026

Emil chooses a positive integer so that

It is between 100100 and 199199 inclusive.
It is divisible by 44.
The sum of its digits is 55
or more.

How many different such integers could Emil choose?

Pick one

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Official solution

Between 100100 and 199199 inclusive, the numbers that are
divisible by 44 are: 4×25=100,4×26=104,4×27=108,4×28=112,,4×49=1964\times25=100, 4\times26=104, 4\times27=108, 4\times28=112, \dots, 4\times49=196 Thus, there are 4925+1=2549-25+1=25 such numbers.

Of these, 100100, 112112 and 120120 are the only numbers whose digit sum
is less than 55.

Therefore, between 100100 and 199199 inclusive, there are 253=2225-3=22 numbers that are divisible by
44 and for which the sum the digits
of each number is 55 or more.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.