Maths Olympiad Prep

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Problem 3

Number theory Difficulty 1.0 Find the answer CEMC Gauss (Grade 8) · Canada · 2014

The number 10 101 is equal to

(A) 1000+100+11000+100+1 (B) 1000+10+11000+10+1 (C) 10000+10+110\,000+10+1 (D) 10000+100+110\,000+100+1 (E) 100000+100+1100\,000+100+1

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

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Official solution

Evaluating, (4×3)+2=12+2=14(4\times3)+2=12+2=14.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.