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Problem 128

Geometry Difficulty 1.1 Multiple choice CEMC Pascal · Canada · 2021

In the diagram, squares of side length 1 meet each other at their vertices.

Figure 0

The perimeter of the figure is

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Official solution

The perimeter of each of the squares of side length 1 is 4×1=44 \times 1 = 4. The perimeters of the 7 squares in the diagram do not overlap, and so the perimeter of the entire figure is 7×4=287 \times 4 = 28.

Figure for this problem

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