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Problem 141

Algebra Difficulty 1.1 Multiple choice CEMC Pascal · Canada · 2023

If 3+△=53 + \triangle = 5 and
△+□=7\triangle + \square = 7, the value
of △+△+△+□+□\triangle + \triangle + \triangle + \square + \square is

Pick one

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Official solution

Since 3+△=53 + \triangle = 5,
then △=5−3=2\triangle = 5 - 3 = 2.

Since △+□=7\triangle + \square = 7 and
△=2\triangle = 2, then □=5\square = 5.

Thus, △+△+△+□+□=3×2+2×5=6+10=16\triangle + \triangle + \triangle + \square + \square = 3 \times 2 + 2 \times 5 = 6 + 10 = 16.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.