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Problem 290

Geometry Difficulty 2.2 Multiple choice CEMC Fermat · Canada · 2019

In the diagram, PQRSPQRS is a rectangle. Also, STU\triangle STU, UVW\triangle UVW and WXR\triangle WXR are congruent.

What fraction of the area of rectangle PQRSPQRS is shaded?

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Official solution

Suppose that SU=UW=WR=bSU=UW=WR=b and PS=hPS=h.

Since the width of rectangle PQRSPQRS is 3b3b and its height is hh, then its area is 3bh3bh.

Since SU=bSU = b and the distance between parallel lines PQPQ and SRSR is hh, then the area of STU\triangle STU is 12bh\frac{1}{2}bh. Similarly, the area of each of UVW\triangle UVW and WXR\triangle WXR is 12bh\frac{1}{2}bh.

Therefore, the fraction of the rectangle that is shaded is 3×12bh3bh\dfrac{3 \times \frac{1}{2}bh}{3bh} which equals 12\dfrac{1}{2}.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.