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Problem 49
Algebra Difficulty 1.1 Multiple choice CEMC Pascal · Canada · 2022
The value of 21+42+84+168
is
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Official solution
In the given sum, each of the four fractions is equivalent to
21.
Therefore, the given sum is equal to $21+21+21+21 = 2$.
Source: CEMC, University of Waterloo,
licensed CC-BY-NC-4.0.
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