The remainder when 111 is divided by 10 is 1. The remainder when
111 is divided by the positive integer is 6. The number of possible values of
is
Problem 551
Pick one
Official solution
Since the remainder when 111 is divided by is 6, then is a multiple of and (since, by definition, the
remainder must be less than the divisor).
Since , the
positive divisors of 105 are $1, 3, 5, 7, 15,
21, 35, 105$.
Therefore, the possible values of
are 7, 15, 21, 35, 105, of which there are 5.