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Problem 192

Algebra Difficulty 1.3 Multiple choice CEMC Fermat · Canada · 2024

If 10n=10002010^n = 1000^{20}, what is
the value of nn?

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Official solution

Using exponent laws, 100020=(103)20=10601000^{20} = (10^3)^{20} = 10^{60} and so n=60n = 60.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.