Maths Olympiad Prep

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Problem 559

AMC 10/12, early questions
Combinatorics Difficulty 3.6 Multiple choice CEMC Gauss (Grade 8) · Canada · 2024

The Gaussbot factory assembles robots. Each robot comes in one of
three colours: red, blue, or green. Each robot also has a number stamped
on its head: 11, 22, 33, or 44. The nnth robot assembled is the first robot to
have the same colour and the same number as a previously assembled
robot. What is the greatest possible value of nn?

Pick one

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Official solutions — 2

Solution 1

There are 33 different
colours and 44 different numbers,
and therefore 3×4=123\times 4=12
different kinds of robots that may be assembled. (These are R1, R2, R3,
R4, B1, B2, B3, B4, G1, G2, G3, G4, where R, B, G represent the 33 colours red, blue, green.)

Since there are 1212 different kinds
of robots, it is possible that the first 1212 robots assembled are all different
from one another.

In this case, the 1313th robot
assembled would be the first robot to have the same colour and the same
number as a previously assembled robot, and thus the greatest possible
value of nn is 1313.

Notes:

It is possible that the first duplicate occurs earlier, but we
want the latest that it can occur.
There must be a duplicate robot among the first 1313 assembled, and so n<14n<14.
This solution makes use of the Pigeonhole principle – a
concept worth further investigation.

Solution 2

There are 33 different
colours and 44 different numbers,
and therefore 3×4=123\times 4=12
different kinds of robots that may be assembled. (These are R1, R2, R3,
R4, B1, B2, B3, B4, G1, G2, G3, G4, where R, B, G represent the 33 colours red, blue, green.)

Since there are 1212 different kinds
of robots, it is possible that the first 1212 robots assembled are all different
from one another.

In this case, the 1313th robot
assembled would be the first robot to have the same colour and the same
number as a previously assembled robot, and thus the greatest possible
value of nn is 1313.

Notes:

It is possible that the first duplicate occurs earlier, but we
want the latest that it can occur.
There must be a duplicate robot among the first 1313 assembled, and so n<14n<14.
This solution makes use of the Pigeonhole principle – a
concept worth further investigation.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.