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Problem 182

Number theory Difficulty 1.4 Multiple choice CEMC Pascal · Canada · 2014

In the subtraction shown, XX and YY are digits. What is the value of X+YX+Y?

Pick one

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Official solution

We rearrange the given subtraction to create the addition statement 45+8Y=1X245+8Y=1X2.

Next, we consider the units digits.

From the statement, the sum 5+Y5+Y has a units digit of 2. This means that Y=7Y=7. This is the only possibility. Therefore, we have 45+87=1X245+87 = 1X2.

But 45+87=13245+87=132, so X=3X=3.

Therefore, X+Y=3+7=10X+Y=3+7=10.

(We can check that 13287=45132 - 87 = 45, as required.)

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.