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Problem 227

Geometry Difficulty 1.4 Multiple choice CEMC Gauss (Grade 7) · Canada · 2023

In the diagram, BCDBCD is a straight line segment.Figure 0The measure of ABC\angle ABC is

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Official solution

Since BCDBCD is a straight line segment, then $\$\angle BCD
=180°=180\degree.Therefore,. Therefore, \angle ACB =BCDACD=180°75°=105°=\angle BCD-\angle ACD=180\degree-75\degree=105\degree. Since the sum of the three angles in

Figure for this problem\triangle ABCis is 180°180\degree,then, then ABC=180°105°35°=40°$.\angle ABC=180\degree-105\degree-35\degree=40\degree\$.

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