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Problem 544

AMC 10/12, early questions
Combinatorics Difficulty 3.5 Find the answer CEMC Fermat · Canada · 2012

Oranges are placed in a pyramid-like stack with each layer completely filled. The base is a rectangle that is 5 oranges wide and 7 oranges long. Each orange, above the first layer, rests in a pocket formed by four oranges in the layer below, as shown. The last layer is a single row of oranges. The total number of oranges in the stack is

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

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Official solution

Because of the way in which the oranges are stacked, each layer is a rectangle whose length is 1 orange less and whose width is 1 orange less than the layer below.

The bottom layer is 5 by 7 and so contains 35 oranges.

The next layer is 4 by 6 and so contains 24 oranges.

The next layer is 3 by 5 and so contains 15 oranges.

The next layer is 2 by 4 and so contains 8 oranges.

The next layer is 1 by 3 and so contains 3 oranges. This is the last layer, as it consists of a single row of oranges.

The total number of oranges in the stack is thus 35+24+15+8+3=8535+24+15+8+3=85.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.