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Problem 562

AMC 10/12, early questions
Combinatorics Difficulty 3.6 Multiple choice CEMC Fermat · Canada · 2025

A tennis tournament starts with 88 players. Francesca is equally likely to
play against any of the other 77
players in her first match. If Francesca plays against Dominique or
Estella, the probability that Francesca wins is 25\frac{2}{5}. If Francesca plays against
any of the other 55 players, the
probability that she wins is 34\frac{3}{4}. What is the probability that
Francesca wins her first match?

Pick one

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Official solution

The probability that Francesca wins her first game is equal to
the probability that she plays either Dominique or Estella and wins,
added to the probability that she plays any of the other 55 players and wins.

It is equally likely that Francesca plays her first game against any of
the other 77 players, and so the
probability that she plays against either Dominique or Estella is 27\dfrac27.

The probability that she wins her first game when playing either of
these two players is 25\dfrac25, and
so the probability that she plays her first match against Dominique or
Estella and wins is 27×25=435\dfrac27\times\dfrac25=\dfrac{4}{35}.

The probability that Francesca plays her first game against any of the
other 55 players is 57\dfrac57.

The probability that she wins her first game when playing any of the
other 55 players is 34\dfrac34, and so the probability that she
plays her first match against any of the other 55 players and wins is 57×34=1528\dfrac57\times\dfrac34=\dfrac{15}{28}.

Thus, the probability that Francesca wins her first match is 435+1528=16140+75140=91140=1320\dfrac{4}{35}+\dfrac{15}{28}=\dfrac{16}{140}+\dfrac{75}{140}=\dfrac{91}{140}=\dfrac{13}{20}.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.