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Problem 1461

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Geometry Difficulty 5.9 Prove it Team Selection Tests for JBMO · Saudi Arabia · 2018

Let ABCABC be a triangle inscribed in circle (O)(O) with incenter II. The lines IBIB and ICIC intersect (O)(O) again at JJ and LL. Circumcircle (ω)(\omega) of triangle IBCIBC meets CACA, ABAB again at EE, FF. Prove that ELEL and FJFJ intersect on (ω)(\omega).

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

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Official solution

Denote XX as the other intersection of (IJL)(IJL) and (ω)(\omega). We shall prove that XX is the intersection of ELEL and FJFJ.

By the cyclic quadrilateral, we have
LXI=LJI=LJB=LCB=LCA=180EXI. \angle LXI = \angle LJI = \angle LJB = \angle LCB = \angle LCA = 180^\circ - \angle EXI.
Hence LL, XX, EE are collinear, which means XX belongs to ELEL.

Similarly, JFJF passes through XX. These finish our proof.

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