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Suppose $f(x)$ is an odd function with domain $\mathbb{R}$. If $f(1) = 2$, $f(2) = 3$, then the value of $f(f(-1))$ is ______.

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Official solution

By the given conditions we have $f(-1) = -f(1) = -2$. Therefore,
$$f(f(-1)) = f(-2) = -f(2) = -3.$$

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.