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Problem 985

AMC 12 late, AIME early
Geometry Difficulty 4.8 Prove it Berkeley Math Circle: Monthly Contest 4 · United States

In a convex nn-sided polygon, all the diagonals are drawn and no three of them pass through a point. Find a formula for the number of regions formed inside the polygon.

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

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Official solution

Solution:

To start with, there is one region inside the nn-gon. A new region is created each time a new diagonal is drawn or two diagonals intersect. The number of diagonals is (n2)n\binom{n}{2} - n, since each diagonal corresponds to a pair of non-adjacent vertices. The number of intersections of two diagonals is (n4)\binom{n}{4}, since each set of four vertices determines a unique pair of intersecting diagonals. Thus, the total number of regions formed is

1+(n2)n+(n4) 1 + \binom{n}{2} - n + \binom{n}{4}

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.