Review the given condition as
pq(2r+50)=pr(7q+55)=qr(8p+12)=A.
This implies that A is a multiple of p, q and r so the value K=pqrA is an integer. Dividing through, we have
K=8+p12=7+q55=2+r50.
Hence, p∣12, q∣55, r∣50. So we have 3 cases as follow
- p=2, q=11, r=5.
- p=3, q=11, r=5.
- p=3, q=5, r=2.
We can check that only (p,q,r)=(3,11,5) works so K=12 and the value of A is 1980. □