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Problem 807

AMC 12 late, AIME early
Number theory Difficulty 4.5 Find the answer Philippine Mathematical Olympiad · Philippines

What is the remainder when 320203^{2020} is divided by 7373?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

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Official solution

Solution:
By Fermat's Little Theorem, 32016=(372)281(mod73)3^{2016} = \left(3^{72}\right)^{28} \equiv 1 \pmod{73}. Therefore, 32020348(mod73)3^{2020} \equiv 3^{4} \equiv 8 \pmod{73}.

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