Olympiad Maths Prep

Track / Stage 3 / 204 of 260 #204 of 2000

Problem 204

AMC 10/12, early questions
Number theory Difficulty 3.8 Find the answer Lista 6 · Brazil

Problem:

Dois divisores - O número 24812^{48} - 1 é divisível por dois números compreendidos entre 60 e 70. Quais são esses números?
(a) 61 e 63
(b) 61 e 65
(c) 63 e 65
(d) 63 e 67
(e) 67 e 69

Official solution

Solution:

Lembre que
a41=(a1)(a3+a2+a+1) a^{4}-1=(a-1)\left(a^{3}+a^{2}+a+1\right)
Logo, se a=212a=2^{12}, temos:
2481=(212)41=(2121)(236+224+212+1) 2^{48}-1=\left(2^{12}\right)^{4}-1=\left(2^{12}-1\right)\left(2^{36}+2^{24}+2^{12}+1\right)
e 2121=(26+1)(261)=65×632^{12}-1=\left(2^{6}+1\right)\left(2^{6}-1\right)=65 \times 63. A opção correta é (c).

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