Olympiad Maths Prep

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Problem 249

AMC 10/12, early questions
Algebra Difficulty 3.9 Find the answer Harvard-MIT November Tournament · United States

Problem:

Let xx be a real number such that 2x=32^{x} = 3. Determine the value of 43x+24^{3x+2}.

Official solution

Solution:

We have
43x+2=43x42=(22)3x16=26x16=(2x)616=3616=11664 4^{3x+2} = 4^{3x} \cdot 4^{2} = \left(2^{2}\right)^{3x} \cdot 16 = 2^{6x} \cdot 16 = \left(2^{x}\right)^{6} \cdot 16 = 3^{6} \cdot 16 = 11664

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