Maths Olympiad Prep

Track / Stage 3 / 105 of 260 #105 of 1964

Problem 105

AMC 10/12, early questions
Algebra Difficulty 3.2 Find the answer

Given that mm is a real constant, proposition pp: xR\forall x \in \mathbb{R}, x24x+2m0x^2 - 4x + 2m \geq 0, then "m3m \geq 3" is the ("blank") for "proposition pp is true".

Pick one

Official solution

When proposition pp is true, xR\forall x \in \mathbb{R}, x24x+2m0x^2 - 4x + 2m \geq 0 always holds. This means that the discriminant Δ=168m0\Delta = 16 - 8m \leq 0, which implies m2m \geq 2.

Since "m3m \geq 3" is a sufficient but not necessary condition for "m2m \geq 2", it follows that "m3m \geq 3" is a sufficient but not necessary condition for "proposition pp is true".

Therefore, the answer is: A\boxed{\text{A}}.

From the quadratic inequality, we have Δ=168m0\Delta = 16 - 8m \leq 0, which gives m2m \geq 2. Using the concept of necessary and sufficient conditions, we find that "m3m \geq 3" is a sufficient but not necessary condition for "m2m \geq 2", and thus we obtain the solution. This problem tests the understanding of quadratic inequalities and necessary and sufficient conditions, and it is considered a simple problem.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.