Maths Olympiad Prep

Track / Stage 5 / 38 of 400 #638 of 1964

Problem 638

AIME late
Geometry Difficulty 5.1 Find the answer

3.38. The lateral faces of a triangular pyramid are equal in area and form angles α,β\alpha, \beta and γ\gamma with the base. Find the ratio of the radius of the sphere inscribed in this pyramid to the radius of the sphere that touches the base of the pyramid and the extensions of the lateral faces.

A number or a short expression. Spacing and $ signs are ignored.

Official solution

3.38. Let rr and rr^{\prime} be the radii of the inscribed and exscribed spheres, SS the area of the lateral face, ss the area of the base, and VV the volume of the pyramid. Then V=(3S+s)r/3V=(3 S+s) r / 3. Similarly, it can be shown that V=(3Ss)r/3V=(3 S-s) r^{\prime} / 3. Moreover, s=(cosα+cosβ+cosγ)Ss=(\cos \alpha + \cos \beta + \cos \gamma) S (see problem 2.13). Therefore,

rr=3Ss3S+s=3cosαcosβcosγ3+cosα+cosβ+cosγ \frac{r}{r^{\prime}}=\frac{3 S-s}{3 S+s}=\frac{3-\cos \alpha-\cos \beta-\cos \gamma}{3+\cos \alpha+\cos \beta+\cos \gamma}

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.