5. Solve the inequality .
Track / Stage 4 / 138 of 340 #398 of 1964
Problem 398
AMC 12 late, AIME early Algebra Difficulty 4.8 Find the answer
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Official solution
Solution: 3x+1x+2≤2x−1x−2;3x+1x+2−2x−1x−2≤0,(3x+1)(2x−1)(x+2)(2x−1)−(x−2)(3x−1)≤0, (3x+1)(2x−1)2x2+3x−2−3x2+5x+2≤0,(3x+1)(2x−1)−8x2+8x≤0,(3x+1)(2x−1)−x(x−8)≤0
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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.