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Problem 486
AMC 12 late, AIME early Algebra Difficulty 4.9 Find the answer
Problem 9-1. Calculate the sum 12+22−32−42+52+62−72−82+92+102−…+20172+20182.
A number or a short expression. Spacing, $ signs and \frac vs / are all fine.
Official solution
Answer: 4074341.
Solution. Note that for any k the equality k2−(k+1)2−(k+2)2+(k+3)2=4 holds. Therefore, the entire sum is equal to 1+504⋅4+20182=4074341.
Source: NuminaMath-1.5,
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