Maths Olympiad Prep

Track / Stage 6 / 253 of 400 #1253 of 1964

Problem 1253

National olympiad, first round
Geometry Difficulty 6.3 Find the answer

On a Cartesian coordinate plane, points (1,2)(1, 2) and (7,4)(7, 4) are opposite vertices of a square. What is the area of the square?

A number or a short expression. Spacing, $ signs and \frac vs / are all fine.

Official solution

1. Identify the coordinates of the opposite vertices of the square:
The given points are (1,2)(1, 2) and (7,4)(7, 4).

2. Calculate the length of the diagonal of the square:
The length of the diagonal can be found using the distance formula:
d=(x2x1)2+(y2y1)2 d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
Substituting the given points (1,2)(1, 2) and (7,4)(7, 4):
d=(71)2+(42)2=62+22=36+4=40 d = \sqrt{(7 - 1)^2 + (4 - 2)^2} = \sqrt{6^2 + 2^2} = \sqrt{36 + 4} = \sqrt{40}

3. Relate the diagonal to the side length of the square:
For a square with side length ss, the diagonal dd is given by:
d=s2 d = s\sqrt{2}
Given that the diagonal d=40d = \sqrt{40}, we can set up the equation:
40=s2 \sqrt{40} = s\sqrt{2}

4. **Solve for the side length ss:**
s=402=402=20 s = \frac{\sqrt{40}}{\sqrt{2}} = \sqrt{\frac{40}{2}} = \sqrt{20}

5. Calculate the area of the square:
The area AA of a square with side length ss is given by:
A=s2 A = s^2
Substituting s=20s = \sqrt{20}:
A=(20)2=20 A = (\sqrt{20})^2 = 20

Conclusion:
20 \boxed{20}

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.