Maths Olympiad Prep

Track / Stage 5 / 163 of 400 #763 of 1964

Problem 763

AIME late
Number theory Difficulty 5.4 Find the answer

2. (1988 US Mathcounts Math Competition) In a game, answering an easy question scores 3 points, and answering a hard question scores 7 points. Among the set of integers that cannot be the total score of a contestant, find the maximum value.

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A number or a short expression. Spacing and $ signs are ignored.

Official solution

2. Let the set of natural numbers that cannot be used as total scores be SS. Among the first 12 natural numbers, only 1,2,4,5,8,111,2,4,5,8,11 belong to SS.

Since 7=2×3+1,3×5=7×2+17=2 \times 3+1,3 \times 5=7 \times 2+1, when the sum of several 3s and 7s n12n \geqslant 12, one can replace a 7 with two 3s, or replace five 3s with two 7s, to increase the sum by 1. Therefore, natural numbers greater than 12 do not belong to SS. So
S={1,2,4,5,8,11} S=\{1,2,4,5,8,11\} \text {. }

The maximum value sought is 11.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.