Maths Olympiad Prep

Track / Stage 4 / 335 of 340 #595 of 1964

Problem 595

AMC 12 late, AIME early
Algebra Difficulty 5.0 Find the answer

4. Let f(x)=ax+bf(x)=a x+b (where a,ba, b are real numbers), f1(x)=f(x),fn+1(x)=f(fn(x)),n=1f_{1}(x)=f(x), f_{n+1}(x)=f\left(f_{n}(x)\right), n=1, 2,3,2,3, \cdots, If 2a+b=22 a+b=-2, and fk(x)=243x+244f_{k}(x)=-243 x+244, then k=k=

A number or a short expression. Spacing and $ signs are ignored.

Official solution

4. 5 Detailed Explanation: We can first find f1(x),f2(x),f3(x)f_{1}(x), f_{2}(x), f_{3}(x), and by induction we get fk(x)=akx+1ak1abf_{k}(x)=a^{k} x+\frac{1-a^{k}}{1-a} \cdot b. Substituting the known values, we can solve for the result.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.