Olympiad Maths Prep

Track / Stage 3 / 55 of 260 #55 of 2000

Problem 55

AMC 10/12, early questions
Geometry Difficulty 3.2 Find the answer

The perimeter of a rectangle is 36 meters, and it is known that the length is three times the width. The area of this rectangle is \_\_\_\_\_\_.

Official solution

First, divide the perimeter by 2 and then by the sum of the ratio of length to width (1+3),
=36÷2÷(1+3)= 36 \div 2 \div (1+3),
=18÷4= 18 \div 4,
=4.5= 4.5 (meters),
The width is 4.5 meters, and since the length is three times the width, 4.5×3=13.54.5 \times 3 = 13.5 (meters),
The area of the rectangle is 13.5×4.5=60.7513.5 \times 4.5 = 60.75 (square meters),
Answer: The area of this rectangle is 60.7560.75 square meters,
Therefore, the answer is 60.75\boxed{60.75} square meters.
Given the perimeter of the rectangle is 36 meters, we know that the sum of length and width is 36÷236 \div 2. Based on "the length is three times the width," if we consider the width as one part, the length is three parts. From this, we can find one part and then calculate the length and width. Finally, using the formula for the area of a rectangle S=abS = ab, we can find the area of this rectangle.
The key is to flexibly use the formula for the perimeter of a rectangle C=(a+b)×2C = (a+b) \times 2 and the formula for the area of a rectangle S=abS = ab to solve the problem.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.