Problem 56

Given that $a$ is the largest negative integer, $b$ is the smallest positive integer, and $c$ is the number with the smallest absolute value, we can determine the values of $a$, $b$, and $c$ as follows:

- Since $a$ is the largest negative integer, $a = -1$.
- Since $b$ is the smallest positive integer, $b = 1$.
- Since $c$ is the number with the smallest absolute value, $c = 0$.

Now, we need to find the value of $a+c-b$. Substituting the values of $a$, $b$, and $c$ we get:

$$a+c-b = -1 + 0 - 1 = -1 - 1 = -2$$

Therefore, the answer is $\boxed{-2}$.