Olympiad Maths Prep

Track / Stage 4 / 70 of 340 #330 of 2000

Problem 330

AMC 12 late, AIME early
Algebra Difficulty 4.7 Find the answer

 1. a>0, and lg(49a2)lga2+4914a=1 \text { 1. } a>0 \text {, and } \lg \left(49-a^{2}\right)-\lg \sqrt{a^{2}+49-14 a}=1

Then a=a=

Official solution

,1.3-, 1.3

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.