Example 4 As shown in Figure 4, in rhombus ABCD, ∠ABC=120∘,F is the midpoint of DC, and the extension of AF intersects the extension of BC at point E. Then the degree measure of the acute angle formed by line BF and DE is ( ). (A) 30∘ (B) 40∘ (C) 50∘ (D) 60∘ (2008, National Junior High School Mathematics League Wuhan CASIO Cup Selection Competition)
Official solution
As shown in Figure 4, let BF intersect DE at point M, and connect BD. Then △BCD is an equilateral triangle. From F being the midpoint of CD, we know ∠MBC=30∘. Since AD//CE, then △ADF and △ECF are centrally symmetric about point F. Therefore, CE=AD=CD. Thus, ∠CEM=30∘,∠DMF=60∘.
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