Maths Olympiad Prep

Track / Stage 5 / 52 of 400 #652 of 1964

Problem 652

AIME late
Geometry Difficulty 5.2 Prove it

[ Intersecting Circles ]] [Symmetry helps solve the problem.]

Two equal circles with centers O1O_{1} and O2O_{2} intersect at points AA and BB. The segment O1O2O_{1} O_{2} intersects these circles at points MM and NN.

Prove that the quadrilaterals O1AO2BO_{1} A O_{2} B and AMBNA M B N are rhombuses.

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

Official solution

The sides of the quadrilateral O1AO2BO_{1} A O_{2} B are equal to the radii of the circles. The diagonals of the quadrilateral AMBNA M B N are perpendicular to each other and are bisected by the point of intersection.

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Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.