Maths Olympiad Prep

Track / Stage 5 / 5 of 400 #605 of 1964

Problem 605

AIME late
Algebra Difficulty 5.0 Find the answer

6. Given tt is a real number. Find all functions f:RRf: \mathbf{R} \rightarrow \mathbf{R} such that
f(x+t+f(y))=f(f(x))+f(t)+y. f(x+t+f(y))=f(f(x))+f(t)+y .
(2014, Croatian Mathematical Olympiad)

A number or a short expression. Spacing and $ signs are ignored.

Official solution

Let x=y=tx=y=-t, we get f(t)=tf(t)=t.
Let x=t,y=tx=-t, y=t, we get f(f(t))=tf(f(-t))=-t.
Let f(t)=a,x=t,y=af(-t)=a, x=t, y=a, we get a=ta=-t.
Finally, let y=ty=-t and x=tx=-t, we get the solution of the function as f(x)=xf(x)=x.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.