Maths Olympiad Prep

Track / Stage 6 / 101 of 400 #1101 of 1964

Problem 1101

National olympiad, first round
Geometry Difficulty 6.1 Prove it

3. Circles k,lk, l intersect at points A,BA, B. Let K,LK, L be the points of tangency of their common tangent chosen such that point BB is an interior point of triangle AKLAKL. On circles kk and ll, choose points NN and MM respectively, such that point AA is an interior point of segment MNMN. Prove that quadrilateral KLMNKLMN is cyclic if and only if line MNMN is tangent to the circumcircle of triangle AKLAKL.

This one wants a proof. Work it on paper, then read the official solution and mark yourself. Be honest about it: the record is only any use to you if it is.

Official solution

SOLUTION. From the equality of the arc and the segment angle corresponding to the chord AKA K of the circle kk, it follows (Fig. 1) that KNA=LKA|\angle K N A|=|\angle L K A|, and similarly, from the equality of the arc and the segment angle corresponding to the chord ALA L of the circle ll, it follows that VLM=LAM|\angle V L M|=|\angle L A M|, where we have denoted by VV some point on the half-line opposite to the half-line LKL K.

!

Fig. 1

The quadrilateral KLMNK L M N is cyclic if and only if KNA=VLM|\angle K N A|=|\angle V L M| or LKA=LAM|\angle L K A|=|\angle L A M|. The last equality holds if and only if LAM\angle L A M is the segment angle corresponding to the arc angle LKA\angle L K A of the chord LAL A of the circumcircle of triangle AKLA K L, i.e., if and only if the line MNM N is tangent to this circle.

This completes the proof of the statement.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.