Maths Olympiad Prep

Track / Stage 3 / 75 of 260 #75 of 1964

Problem 75

AMC 10/12, early questions
Geometry Difficulty 3.2 Find the answer

In a regular nn-sided polygon, the measure of each interior angle is 55 times the measure of its adjacent exterior angle. Find the value of nn.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Official solution

To solve the problem, let's denote the measure of each exterior angle of the polygon as xx degrees. Given that the measure of each interior angle is 55 times the measure of its adjacent exterior angle, we can express the measure of each interior angle as 5x5x degrees.

Since the interior and exterior angles are supplementary (they add up to 180180^{\circ}), we can set up the equation:
x+5x=180x + 5x = 180^{\circ}

Simplifying this equation involves combining like terms:
6x=1806x = 180^{\circ}

To find the value of xx, we divide both sides of the equation by 66:
x=1806=30x = \frac{180^{\circ}}{6} = 30^{\circ}

Now that we know each exterior angle measures 3030^{\circ}, we can find the number of sides of the polygon. The sum of all exterior angles of a polygon is always 360360^{\circ}. Therefore, to find the number of sides (nn), we divide the total measure of all exterior angles by the measure of one exterior angle:
n=36030=12n = \frac{360^{\circ}}{30^{\circ}} = 12

Thus, the value of nn, which represents the number of sides of the polygon, is 12\boxed{12}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.