Five positive integers are listed in increasing order. The difference between any two consecutive numbers in the list is three. The fifth number is a multiple of the first number. How many different such lists of five integers are there?
Problem 636
Pick one
Official solution
Suppose the first integer in the list is .
Then the remaining four integers are , and .
Since the fifth number is a multiple of the first, then is an integer. Since is an integer, then is an integer, or is a positive divisor of 12 .
The positive divisors of 12 are , and 12 , so there are 6 possible values of and so 6 different lists.
(We can check that each of 6 values of produces a different list, each of which has the required property.)
ANSwER: (D)