Maths Olympiad Prep

Track / Stage 4 / 181 of 340 #441 of 1964

Problem 441

AMC 12 late, AIME early
Geometry Difficulty 4.8 Find the answer

81 Given a rhombus ABCDA B C D with side length aa and A=π3\angle A=\frac{\pi}{3}, the rhombus ABCDA B C D is folded along the diagonal to form a dihedral angle θ\theta, where θ[π3,2π3]\theta \in\left[\frac{\pi}{3}, \frac{2 \pi}{3}\right]. Then the maximum distance between the two diagonals is
A. 32a\frac{3}{2} a
B. 34a\frac{\sqrt{3}}{4} a
C. 32a\frac{\sqrt{3}}{2} a
D. 34a\frac{3}{4} a

Multiple choice: answer with the letter of the option you want.

Official solution

81 D. If folded along BDB D, let the midpoint of ACA C be FF, and the midpoint of BDB D be EE, then AE=32aA E=\frac{\sqrt{3}}{2} a,
EF=AEcosθ232acosπ6=34a. E F=A E \cos \frac{\theta}{2} \leqslant \frac{\sqrt{3}}{2} a \cos \frac{\pi}{6}=\frac{3}{4} a .

If folded along ACA C, let the midpoint of ACA C be FF, and the midpoint of BDB D be EE, then BD=12a,EF=BDcosθ2B D=\frac{1}{2} a, E F=B D \cos \frac{\theta}{2} \leqslant
3a4. \frac{\sqrt{3} a}{4} .

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.