Maths Olympiad Prep

Track / Stage 5 / 99 of 400 #699 of 1964

Problem 699

AIME late
Number theory Difficulty 5.3 Find the answer

17. The greatest common divisor of two natural numbers is 12, and their least common multiple is 672. What are these numbers if it is known that the smaller of them is divisible by 7, and the larger is not?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Official solution

17. Let aa and bb be the sought numbers. Since D(a,b)=12D(a, b) = 12, it follows that a=12xa = 12x and b=12yb = 12y, where xx and yy are relatively prime natural numbers, i.e., D(x,y)=1D(x, y) = 1.

Given the equality D(a,b)V(a,b)=abD(a, b) \cdot V(a, b) = a \cdot b, we have 12672=12x12y12 \cdot 672 = 12x \cdot 12y, which simplifies to

12xy=67212xy = 672, i.e., xy=56xy = 56.

We now have the following possibilities:

xx1247
yy5628148
D(x,y)D(x, y)1221

Since the numbers xx and yy are relatively prime, and given that the smaller of them is divisible by 7, while the larger is not, we conclude that the only solution is obtained for x=7x = 7 and y=8y = 8.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.