Maths Olympiad Prep

Track / Stage 5 / 270 of 400 #870 of 1964

Problem 870

AIME late
Algebra Difficulty 5.6 Find the answer

4. Mr. Perić arrived in Matkograd on Friday and ordered a taxi. The driver explained that the departure fee is 20 kuna, plus an additional 5 kuna for each kilometer traveled. On Saturday, he used the services of the same taxi company, but that day, due to the anniversary of the company's founding, all driving bills were reduced by 20%20 \%. That day, Mr. Perić traveled 5 km5 \mathrm{~km} more than on Friday, and he paid the same amount of money. How many kilometers did Mr. Perić travel on Friday, and how many on Saturday, and how much did he pay for one taxi ride?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Official solution

4. Let sx\mathrm{s} x be the number of kilometers Mr. Perić walked on Friday.

For this distance, he would have to pay [20+5x][20+5 x] kuna since there was no discount on Friday.

1 POINT

On Saturday, Mr. Perić walked 5 km5 \mathrm{~km} more, i.e., [x+5][x+5] kilometers, which would cost him [20+(5(x+5))][20+(5(x+5))] kuna, or [45+5x][45+5 x] kuna,

but with a 20%20 \% discount, he pays 80%80 \% of the price, which means he pays [0.8 (45 + 5x)] kuna, or [36+4x][36+4 x] kuna.

1 POINT

Since he paid the same amount of money on Saturday as on Friday, the equation is

0.8(45+5x)=20+5x0.8(45+5 x)=20+5 x,

1 POINT

36+4x=20+5x36+4 x=20+5 x,

x=16x=16. 1 POINT

Therefore, Mr. Perić walked 16 km16 \mathrm{~km} on Friday and 21 km21 \mathrm{~km} on Saturday. 1 POINT

For one ride, he paid 20+165=20+80=10020+16 \cdot 5=20+80=100 kuna. 1 POINT

TOTAL 6 POINTS

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.