Maths Olympiad Prep

Track / Stage 7 / 234 of 300 #1634 of 1964

Problem 1634

National olympiad second round; IMO P1/P4
Geometry Difficulty 7.5 Find the answer

Giiven ΔABC\Delta ABC, CAB=75\angle CAB=75^{\circ} and ACB=45\angle ACB=45^{\circ}. BCBC is extended to TT so that BC=CTBC=CT. Let MM be the midpoint of the segment ATAT. Find BMC\angle BMC.

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Official solution

1. Given ΔABC\Delta ABC with CAB=75\angle CAB = 75^\circ and ACB=45\angle ACB = 45^\circ. We need to find BMC\angle BMC where BCBC is extended to TT such that BC=CTBC = CT and MM is the midpoint of ATAT.
2. Draw the altitude from vertex AA to BCBC and call the intersection point HH. This gives us two right triangles ΔABH\Delta ABH and ΔAHC\Delta AHC.
3. Since CAB=75\angle CAB = 75^\circ and ACB=45\angle ACB = 45^\circ, we can find BAH\angle BAH and HAC\angle HAC:
BAH=7545=30 \angle BAH = 75^\circ - 45^\circ = 30^\circ
HAC=45 \angle HAC = 45^\circ
4. Let BH=xBH = x. Then, using trigonometric ratios in ΔABH\Delta ABH and ΔAHC\Delta AHC:
AB=2x(since sin30=12) AB = 2x \quad (\text{since } \sin 30^\circ = \frac{1}{2})
AH=x3(since tan30=13) AH = x\sqrt{3} \quad (\text{since } \tan 30^\circ = \frac{1}{\sqrt{3}})
HC=x3(since tan45=1) HC = x\sqrt{3} \quad (\text{since } \tan 45^\circ = 1)
AC=x6(using Pythagoras’ theorem in ΔAHC) AC = x\sqrt{6} \quad (\text{using Pythagoras' theorem in } \Delta AHC)
5. Since BC=CTBC = CT, AM=MTAM = MT implies MM is the midpoint of ATAT. Therefore, MCMC is the midsegment of ABT\triangle ABT and MC=xMC = x.
6. BMBM and ACAC are medians. Let KK be the intersection point of BMBM and ACAC. KK is the centroid of ABC\triangle ABC.
7. The centroid divides each median in the ratio 2:12:1. Therefore:
AKKC=2    AK=2x23,KC=x23 \frac{AK}{KC} = 2 \implies AK = \frac{2x\sqrt{2}}{\sqrt{3}}, \quad KC = \frac{x\sqrt{2}}{\sqrt{3}}
8. Using the Law of Cosines in KMC\triangle KMC:
KM2=KC2+CM22KCCMcos75 KM^2 = KC^2 + CM^2 - 2 \cdot KC \cdot CM \cdot \cos 75^\circ
We know cos75=624\cos 75^\circ = \frac{\sqrt{6} - \sqrt{2}}{4}, so:
KM2=(x23)2+x22x23x624 KM^2 = \left(\frac{x\sqrt{2}}{\sqrt{3}}\right)^2 + x^2 - 2 \cdot \frac{x\sqrt{2}}{\sqrt{3}} \cdot x \cdot \frac{\sqrt{6} - \sqrt{2}}{4}
Simplifying the expression:
KM2=2x23+x2x2(126)23 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{12} - \sqrt{6})}{2\sqrt{3}}
KM2=2x23+x2x2(236)23 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(2\sqrt{3} - \sqrt{6})}{2\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
KM2=2x23+x2x2(32)3 KM^2 = \frac{2x^2}{3} + x^2 - \frac{x^2(\sqrt{3} - \sqrt{2})}{\sqrt{3}}
\[
KM^2 =

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.