Example 1 In the tetrahedron ABCD, it is known that AB=AC=AD=DB=5,BC=3,CD=4.
Then the volume of the tetrahedron is .
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Official solution
Given that ∠BCD=90∘. As shown in Figure 1, take the midpoint E of BD and connect AE and CE. By the properties of a right-angled triangle, we have BE=CE=DE. Since AB=AC=AD=DB=5, we have △ABE≅△ACE≅△ADE. Thus, AE⊥BD,AE⊥EC. Therefore, AE⊥ plane BCD, which means AE is the height of plane BCD. The calculation shows that Vtetrahedron ABCD=31S△BCD⋅AE=31×6×253=53.
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