3. Let a=2kπ(k=0,±1,±2,⋯),T≡cosa+cotasina+tana.
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Official solution
(C) 3. 【Analysis and Solution】By making an identity transformation, we easily get T=cosa+cotasina+tana=cota(sina+1)tana(cosa+1)=sina+1(tan2a)(cosa+1)>0. (Where a=2kπ,k=0,±1,±2,⋯)).
Source: NuminaMath-1.5,
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