Track / Stage 4 / 243 of 340 #503 of 1964

Problem 503

AMC 12 late, AIME early

Algebra Difficulty 4.9 Find the answer

4. The sum of several addends is equal to $2 b-1$ . To one addend, $3 b-8$ was added, and from the second, $-b-7$ was subtracted. How much must be subtracted from the third addend so that the sum becomes equal to zero?

Your answer

A number or a short expression. Spacing, $ signs and \frac vs / are all fine.

Official solution

4. Solution. If $x$ is the desired number, then

$2 b-1+(3 b-8)-(-b-7)-x=0 ; x=6 b-2$ .

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.