Problem 24

The prime factorization of $6545$ is $5\cdot7\cdot11\cdot17 =385\cdot17$, which contains a three digit number, but we want 6545 to be expressed as ab x cd. Now we do trial and error:
$$5\cdot7=35 \text{, } 11\cdot17=187 \text{ X}$$ $$5\cdot11=55 \text{, } 7\cdot17=119 \text{ X}$$ $$5\cdot17=85 \text{, } 7\cdot11=77 \text{ }\surd$$ $$85+77= \boxed{\text{(A)}\ 162}$$